计算机等级二级C语言程序设计100例九

3/6/2007来源:软件水平考试人气:13051

  【程序91】

  题目:时间函数举例1

  1.程序分析:

  2.程序源代码:

以下是引用片段:
  #include "stdio.h"
  #include "time.h"
  void main()
  { time_t lt; /*define a longint time varible*/
  lt=time(NULL);/*system time and date*/
  PRintf(ctime(<)); /*english format output*/
  printf(asctime(localtime(<)));/*tranfer to tm*/
  printf(asctime(gmtime(<))); /*tranfer to Greenwich time*/
  }


  【程序92】

  题目:时间函数举例2

  1.程序分析:

  2.程序源代码:

以下是引用片段:
  /*calculate time*/
  #include "time.h"
  #include "stdio.h"
  main()
  { time_t start,end;
  int i;
  start=time(NULL);
  for(i=0;i<3000;i++)
  { printf("\1\1\1\1\1\1\1\1\1\1\n");}
  end=time(NULL);
  printf("\1: The different is %6.3f\n",difftime(end,start));
  }


  【程序93】

  题目:时间函数举例3

  1.程序分析:

  2.程序源代码:

以下是引用片段:
  /*calculate time*/
  #include "time.h"
  #include "stdio.h"
  main()
  { clock_t start,end;
  int i;
  double var;
  start=clock();
  for(i=0;i<10000;i++)
  { printf("\1\1\1\1\1\1\1\1\1\1\n");}
  end=clock();
  printf("\1: The different is %6.3f\n",(double)(end-start));
  }
  【程序94】

  题目:时间函数举例4,一个猜数游戏,判断一个人反应快慢。(版主初学时编的)

  1.程序分析:

  2.程序源代码:

以下是引用片段:
  #include "time.h"
  #include "stdlib.h"
  #include "stdio.h"
  main()
  {char c;
  clock_t start,end;
  time_t a,b;
  double var;
  int i,guess;
  srand(time(NULL));
  printf("do you want to play it.(’y’ or ’n’) \n");
  loop:
  while((c=getchar())==’y’)
  {
  i=rand()0;
  printf("\nplease input number you guess:\n");
  start=clock();
  a=time(NULL);
  scanf("%d",&guess);
  while(guess!=i)
  {if(guess>i)
  {printf("please input a little smaller.\n");
  scanf("%d",&guess);}
  else
  {printf("please input a little bigger.\n");
  scanf("%d",&guess);}
  }
  end=clock();
  b=time(NULL);
  printf("\1: It took you %6.3f seconds\n",var=(double)(end-start)/18.2);
  printf("\1: it took you %6.3f seconds\n\n",difftime(b,a));
  if(var<15)
  printf("\1\1 You are very clever! \1\1\n\n");
  else if(var<25)
  printf("\1\1 you are normal! \1\1\n\n");
  else
  printf("\1\1 you are stupid! \1\1\n\n");
  printf("\1\1 Congradulations \1\1\n\n");
  printf("The number you guess is %d",i);
  }
  printf("\ndo you want to try it again?(\"yy\".or.\"n\")\n");
  if((c=getch())==’y’)
  goto loop;
  }
  【程序95】

  题目:家庭财务管理小程序

  1.程序分析:

  2.程序源代码:

以下是引用片段:
  /*money management system*/
  #include "stdio.h"
  #include "dos.h"
  main()
  {
  FILE *fp;
  struct date d;
  float sum,chm=0.0;
  int len,i,j=0;
  int c;
  char ch[4]="",ch1[16]="",chtime[12]="",chshop[16],chmoney[8];
  pp: clrscr();
  sum=0.0;
  gotoxy(1,1);printf("|---------------------------------------------------------------------------|");
  gotoxy(1,2);printf("| money management system(C1.0) 2000.03 |");
  gotoxy(1,3);printf("|---------------------------------------------------------------------------|");
  gotoxy(1,4);printf("| -- money records -- | -- today cost list -- |");
  gotoxy(1,5);printf("| ------------------------ |-------------------------------------|");
  gotoxy(1,6);printf("| date: -------------- | |");
  gotoxy(1,7);printf("| | | | |");
  gotoxy(1,8);printf("| -------------- | |");
  gotoxy(1,9);printf("| thgs: ------------------ | |");
  gotoxy(1,10);printf("| | | | |");
  gotoxy(1,11);printf("| ------------------ | |");
  gotoxy(1,12);printf("| cost: ---------- | |");
  gotoxy(1,13);printf("| | | | |");
  gotoxy(1,14);printf("| ---------- | |");
  gotoxy(1,15);printf("| | |");
  gotoxy(1,16);printf("| | |");
  gotoxy(1,17);printf("| | |");
  gotoxy(1,18);printf("| | |");
  gotoxy(1,19);printf("| | |");
  gotoxy(1,20);printf("| | |");
  gotoxy(1,21);printf("| | |");
  gotoxy(1,22);printf("| | |");
  gotoxy(1,23);printf("|---------------------------------------------------------------------------|");
  i=0;
  getdate(&d);
  sprintf(chtime,"M.d.d",d.da_year,d.da_mon,d.da_day);
  for(;;)
  {
  gotoxy(3,24);printf(" Tab __browse cost list Esc __quit");
  gotoxy(13,10);printf(" ");
  gotoxy(13,13);printf(" ");
  gotoxy(13,7);printf("%s",chtime);
  j=18;
  ch[0]=getch();
  if(ch[0]==27)
  break;
  strcpy(chshop,"");
  strcpy(chmoney,"");
  if(ch[0]==9)
  {
  mm:i=0;
  fp=fopen("home.dat","r+");
  gotoxy(3,24);printf(" ");
  gotoxy(6,4);printf(" list records ");
  gotoxy(1,5);printf("|-------------------------------------|");
  gotoxy(41,4);printf(" ");
  gotoxy(41,5);printf(" |");
  while(fscanf(fp,"ss%f\n",chtime,chshop,&chm)!=EOF)
  { if(i==36)
  { getch();
  i=0;}
  if ((i6)<17)
  { gotoxy(4,6+i);
  printf(" ");
  gotoxy(4,6+i);}
  else
  if((i6)>16)
  { gotoxy(41,4+i-17);
  printf(" ");
  gotoxy(42,4+i-17);}
  i++;
  sum=sum+chm;
  printf("s %-14s %6.1f\n",chtime,chshop,chm);}
  gotoxy(1,23);printf("|---------------------------------------------------------------------------|");
  gotoxy(1,24);printf("| |");
  gotoxy(1,25);printf("|---------------------------------------------------------------------------|");
  gotoxy(10,24);printf("total is %8.1f$",sum);
  fclose(fp);
  gotoxy(49,24);printf("press any key to.....");getch();goto pp;
  }
  else
  {
  while(ch[0]!=’\r’)
  { if(j<10)
  { strncat(chtime,ch,1);
  j++;}
  if(ch[0]==8)
  {
  len=strlen(chtime)-1;
  if(j>15)
  { len=len+1; j=11;}
  strcpy(ch1,"");
  j=j-2;
  strncat(ch1,chtime,len);
  strcpy(chtime,"");
  strncat(chtime,ch1,len-1);
  gotoxy(13,7);printf(" ");}
  gotoxy(13,7);printf("%s",chtime);ch[0]=getch();
  if(ch[0]==9)
  goto mm;
  if(ch[0]==27)
  exit(1);
  }
  gotoxy(3,24);printf(" ");
  gotoxy(13,10);
  j=0;
  ch[0]=getch();
  while(ch[0]!=’\r’)
  { if (j<14)
  { strncat(chshop,ch,1);
  j++;}
  if(ch[0]==8)
  { len=strlen(chshop)-1;
  strcpy(ch1,"");
  j=j-2;
  strncat(ch1,chshop,len);
  strcpy(chshop,"");
  strncat(chshop,ch1,len-1);
  gotoxy(13,10);printf(" ");}
  gotoxy(13,10);printf("%s",chshop);ch[0]=getch();}
  gotoxy(13,13);
  j=0;
  ch[0]=getch();
  while(ch[0]!=’\r’)
  { if (j<6)
  { strncat(chmoney,ch,1);
  j++;}
  if(ch[0]==8)
  { len=strlen(chmoney)-1;
  strcpy(ch1,"");
  j=j-2;
  strncat(ch1,chmoney,len);
  strcpy(chmoney,"");
  strncat(chmoney,ch1,len-1);
  gotoxy(13,13);printf(" ");}
  gotoxy(13,13);printf("%s",chmoney);ch[0]=getch();}
  if((strlen(chshop)==0)||(strlen(chmoney)==0))
  continue;
  if((fp=fopen("home.dat","a+"))!=NULL);
  fprintf(fp,"ss%6s",chtime,chshop,chmoney);
  fputc(’\n’,fp);
  fclose(fp);
  i++;
  gotoxy(41,5+i);
  printf("s %-14s %-6s",chtime,chshop,chmoney);
  }}}

  【程序96】

  题目:计算字符串中子串出现的次数

  1.程序分析:

  2.程序源代码:

以下是引用片段:
  #include "string.h"
  #include "stdio.h"
  main()
  { char str1[20],str2[20],*p1,*p2;
  int sum=0;
  printf("please input two strings\n");
  scanf("%s%s",str1,str2);
  p1=str1;p2=str2;
  while(*p1!=’\0’)
  {
  if(*p1==*p2)
  {while(*p1==*p2&&*p2!=’\0’)
  {p1++;
  p2++;}
  }
  else
  p1++;
  if(*p2==’\0’)
  sum++;
  p2=str2;
  }
  printf("%d",sum);
  getch();}


  【程序97】

  题目:从键盘输入一些字符,逐个把它们送到磁盘上去,直到输入一个#为止。

  1.程序分析:

  2.程序源代码:

以下是引用片段:
  #include "stdio.h"
  main()
  { FILE *fp;
  char ch,filename[10];
  scanf("%s",filename);
  if((fp=fopen(filename,"w"))==NULL)
  {printf("cannot open file\n");
  exit(0);}
  ch=getchar();
  ch=getchar();
  while(ch!=’#’)
  {fputc(ch,fp);putchar(ch);
  ch=getchar();
  }
  fclose(fp);
  }


  【程序98】

  题目:从键盘输入一个字符串,将小写字母全部转换成大写字母,然后输出到一个磁盘文件“test”中保存。

  输入的字符串以!结束。

  1.程序分析:

  2.程序源代码:

以下是引用片段:
  #include "stdio.h"
  main()
  {FILE *fp;
  char str[100],filename[10];
  int i=0;
  if((fp=fopen("test","w"))==NULL)
  { printf("cannot open the file\n");
  exit(0);}
  printf("please input a string:\n");
  gets(str);
  while(str[i]!=’!’)
  { if(str[i]>=’a’&&str[i]<=’z’)
  str[i]=str[i]-32;
  fputc(str[i],fp);
  i++;}
  fclose(fp);
  fp=fopen("test","r");
  fgets(str,strlen(str)+1,fp);
  printf("%s\n",str);
  fclose(fp);
  }


  【程序99】

  题目:有两个磁盘文件A和B,各存放一行字母,要求把这两个文件中的信息合并(按字母顺序排列),

  输出到一个新文件C中。

  1.程序分析:

  2.程序源代码:

以下是引用片段:
  #include "stdio.h"
  main()
  { FILE *fp;
  int i,j,n,ni;
  char c[160],t,ch;
  if((fp=fopen("A","r"))==NULL)
  {printf("file A cannot be opened\n");
  exit(0);}
  printf("\n A contents are :\n");
  for(i=0;(ch=fgetc(fp))!=EOF;i++)
  {c[i]=ch;
  putchar(c[i]);
  }
  fclose(fp);
  ni=i;
  if((fp=fopen("B","r"))==NULL)
  {printf("file B cannot be opened\n");
  exit(0);}
  printf("\n B contents are :\n");
  for(i=0;(ch=fgetc(fp))!=EOF;i++)
  {c[i]=ch;
  putchar(c[i]);
  }
  fclose(fp);
  n=i;
  for(i=0;ifor(j=i+1;jif(c[i]>c[j])
  {t=c[i];c[i]=c[j];c[j]=t;}
  printf("\n C file is:\n");
  fp=fopen("C","w");
  for(i=0;i{ putc(c[i],fp);
  putchar(c[i]);
  }
  fclose(fp);
  }
  【程序100】

  题目:有五个学生,每个学生有3门课的成绩,从键盘输入以上数据(包括学生号,姓名,三门课成绩),计算出

  平均成绩,况原有的数据和计算出的平均分数存放在磁盘文件"stud"中。

  1.程序分析:

  2.程序源代码: 以下是引用片段:
  #include "stdio.h"
  struct student
  { char num[6];
  char name[8];
  int score[3];
  float avr;
  } stu[5];
  main()
  {int i,j,sum;
  FILE *fp;
  /*input*/
  for(i=0;i<5;i++)
  { printf("\n please input No. %d score:\n",i);
  printf("stuN");
  scanf("%s",stu[i].num);
  printf("name:");
  scanf("%s",stu[i].name);
  sum=0;
  for(j=0;j<3;j++)
  { printf("score %d.",j+1);
  scanf("%d",&stu[i].score[j]);
  sum+=stu[i].score[j];
  }
  stu[i].avr=sum/3.0;
  }
  fp=fopen("stud","w");
  for(i=0;i<5;i++)
  if(fwrite(&stu[i],sizeof(struct student),1,fp)!=1)
  printf("file write error\n");
  fclose(fp);
  }